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Cat12511
@Cat12511
July 2022
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представьте квадратный трехчлен 10х^2+9х-9 в виде произведения линейных множителей
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NadDer
10x^2+9x-9 = 0
D = 81-4*(-9)*10 = 81+360 = 441 (кв. корень равен 21)
х1 = (-9+21)/20 = 12\20 = 3\5 = 0,6
х2 = (-9-21)/20 = -30\20 = -3\2 = -1,5
ax^2+bx+c = a(x-x1)(x-x2)
10(x - 0,6)(х+1,5) = (10x-6)(x+1,5)
10x^2+9x-9 = (10x-6)(x+1,5)
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Answers & Comments
D = 81-4*(-9)*10 = 81+360 = 441 (кв. корень равен 21)
х1 = (-9+21)/20 = 12\20 = 3\5 = 0,6
х2 = (-9-21)/20 = -30\20 = -3\2 = -1,5
ax^2+bx+c = a(x-x1)(x-x2)
10(x - 0,6)(х+1,5) = (10x-6)(x+1,5)
10x^2+9x-9 = (10x-6)(x+1,5)