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julya0090
@julya0090
October 2021
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Представьте в виде квадрата двучлена выражение:
1. (а+4)²-2(а+4)+1;
2. (3b+2)²+4(3b+2)+4;
3. (3y+8)²+(4у+6)²+4у;
4. (х-5у)²+(х+12у)²-х(х-12у)
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tamarabernukho
1. (а+4)²-2(а+4)+1=a²+8a+16-2a-8+1=a²+6a+9=(a+3)²
2. (3b+2)²+4(3b+2)+4=9b²+12b+4+12b+8+4=9b²+24b+16=(3b+4)²
3. (3y+8)²+(4у+6)²+4у=16y²+48y+36+4y=25y²+100y+100=(5y+10)²
4. (х-5у)²+(х+12у)²-х(х-12у)=x
²-10xy+25y²+x²+24xy+144y²-x²+12xy=x²+26xy+169y²=(x+13y)²
2 votes
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julya0090
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azimovzukhron
1. a^2+8a+16-2a-8+1=a^2+6a+9=(x+3)^2
2. 9b^2+12b+4+12b+8+4=9b^2+24b+16=(3b+4)^2
3. 9y^2+48y+64+16y^2+48y+36+4y=25y^2+100y+100=(5y+10)^2
4. x^2-10yx+25y^2+x^2+24yx+144y^2-x^2+12yx=x^2+26yx+169y^2=(x+13y)^2
1 votes
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Answers & Comments
2. (3b+2)²+4(3b+2)+4=9b²+12b+4+12b+8+4=9b²+24b+16=(3b+4)²
3. (3y+8)²+(4у+6)²+4у=16y²+48y+36+4y=25y²+100y+100=(5y+10)²
4. (х-5у)²+(х+12у)²-х(х-12у)=x²-10xy+25y²+x²+24xy+144y²-x²+12xy=x²+26xy+169y²=(x+13y)²
2. 9b^2+12b+4+12b+8+4=9b^2+24b+16=(3b+4)^2
3. 9y^2+48y+64+16y^2+48y+36+4y=25y^2+100y+100=(5y+10)^2
4. x^2-10yx+25y^2+x^2+24yx+144y^2-x^2+12yx=x^2+26yx+169y^2=(x+13y)^2