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baymushkina
@baymushkina
August 2022
1
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Представьте в виде многочлена
1). (Б-5) (б-4) - 3б(2б-3)
2). 3х(х-2) - (х-3)в квадрате
3). 5(а+1)в квадрате - 10а
Помогите пожалуйста. Молю
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Answers & Comments
pomoshnik09
1) =b^2-4b-5b+20-6b^2+9b=-5b^2+20
2) =3x²-6x-(x²-6x+9)= 3x²-6x-x²+6x-9=2x²-9
3) = 5(a²+2a+1)-10a=5a²+10a+5-10a=5a²+5
3 votes
Thanks 3
baymushkina
Спасибо огромное =3
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Answers & Comments
2) =3x²-6x-(x²-6x+9)= 3x²-6x-x²+6x-9=2x²-9
3) = 5(a²+2a+1)-10a=5a²+10a+5-10a=5a²+5