Представьте в виде многочлена:
1)(2xy-1)(2xy+1)
2)(8ab+5)(5-8ab)
3)(8+9cd)(9cd-8)
Выполните действия:
1)(a²+b²)(a²-b²)
2)(10m²-n²)(10m²+n²)
3)(5-x)(5+x)(25+x²)
1)(2xy-1)(2xy+1)
2)(8ab+5)(5-8ab)
3)(8+9cd)(9cd-8)
Выполните действия:
1)(a²+b²)(a²-b²)
2)(10m²-n²)(10m²+n²)
3)(5-x)(5+x)(25+x²)
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Verified answer
1) (2xy-1)(2xy+1)= (2xy)² -1²=4x²y²-12) (8ab+5)(5-8ab)=5²-(8ab)²=25-64a²b²
3) (8+9cd)(9cd-8)=(9cd)²-8²=81c²d²-64
1) (a²+b²)(a²-b²)= (a²)² - (b²)²=a^4 - b^4
2) (10m²-n²)(10m²+n²)=100m^4-n^4
3) (5-x)(5+x)(25+x²)= (25-x²)(25+x²)= 625-x^4