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maks200307
@maks200307
August 2021
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представьте в виде многочлена стандартного вида выражение 1) 5a(а4 - 6 а2 + 3)
2)(х+4)(3х-2)
3) (6 м+ 5n)(7m -3n)
4)(x+5)(x2+x-6)
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УмНиЧкА13
1) 5a(a^4-6a^2+3)=5а^5-30a^3+15a=a^5-6^3+3a
2)(x+4)(3x-2)=3x^2-2x+12x-8=3x^2+10x-8
3)(6m+5n)(7m-3n)=42m^2-18mn+35mn-15n^2=42m^2+17mn-15n^2
4)(x+5)(x^2+x-6)=x^3+x^2-6x+5x^2+5x-30=x^3+6x^2-x-30
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Answers & Comments
2)(x+4)(3x-2)=3x^2-2x+12x-8=3x^2+10x-8
3)(6m+5n)(7m-3n)=42m^2-18mn+35mn-15n^2=42m^2+17mn-15n^2
4)(x+5)(x^2+x-6)=x^3+x^2-6x+5x^2+5x-30=x^3+6x^2-x-30