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лиот5
@лиот5
August 2022
1
13
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представьте в виде многочлена выражения:
1) (3p+8) сверху 2
2) (-5с-8d) сверху 2
3) (2m-5n сверху 4)(2m+5n сверху 4)
4) (2m сверху 8 -6n сверху 7 )(-2m сверху 8 -6n сверху 7 )
с решениями
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sebrithien
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1)
2)
3)
4)
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1)
2)
3)
4)