Представьте в виде произведения:
а) (2х-3)^2 - 9
б)16 - (5-6а)^2
а)(2х-3)^2 - 9=(2х-3)^2 - 3^2=(2х-3-3)·(2х-3+3)=2x·(2х-6);
б))16 - (5-6а)^2=4^2-(5-6а)^2=(4-5+6а)·(4+5-6а)=(6a-1)·(9-6a)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
а)(2х-3)^2 - 9=(2х-3)^2 - 3^2=(2х-3-3)·(2х-3+3)=2x·(2х-6);
б))16 - (5-6а)^2=4^2-(5-6а)^2=(4-5+6а)·(4+5-6а)=(6a-1)·(9-6a)