(a+3b)²−4a²=(a+3b-2a)(a+3b+2a)=(3b-a)(3b+3a)=3(3b-a)(b+a)
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(a+3b)²−4a²=(a+3b-2a)(a+3b+2a)=(3b-a)(3b+3a)=3(3b-a)(b+a)