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agron080802
@agron080802
October 2021
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Представьте в виде произведения
х^3+3x^2-4
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fiofionina
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Решение:
x^3+3x^2-4=x^3-1+3x^2-3=(x^3-1)+(3x^2-3)=(x-1)*(x^2+x+1)+3*(x^2-1)=(x-1)*(x^2+x+1)+3*(x-1)*(x+1)=(x-1)*(x^2+x+1)+(x-1)*(3x+3)=(x-1)*(x^2+x+1+3x+3)=(x-1)*(x^2+4x+4)
Ответ: (x-1)*(x^2+4x+4)
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Answers & Comments
Verified answer
Решение:x^3+3x^2-4=x^3-1+3x^2-3=(x^3-1)+(3x^2-3)=(x-1)*(x^2+x+1)+3*(x^2-1)=(x-1)*(x^2+x+1)+3*(x-1)*(x+1)=(x-1)*(x^2+x+1)+(x-1)*(3x+3)=(x-1)*(x^2+x+1+3x+3)=(x-1)*(x^2+4x+4)
Ответ: (x-1)*(x^2+4x+4)