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dashutailyashe
@dashutailyashe
August 2022
1
7
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Представьте в виде произведения многочлен:
1) 2x^3-2xy^2-8x^2+8y^2
2) 5a^2-5b^2-15a^3b+15ab^3
3) a^2b^2-1-b^2+a^2
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Answers & Comments
MizoriesKun
Verified answer
2x^3
-2xy^2-
8x^2
+8y^2 =2x
²(х-4)-2у²(х-4) =(х-4)(2х²-2у²)=2(х-4)(х²-у²)=
=2(х-4)*х-у)*(х+у)
5a^2-5b^2
-15a^3b+15ab^3=5(a
²-b²)-15ab(a²-b²)=(a²-b²
)(5-15ab)=
=5(a-b)(a+b)(1-3ab)
a^2b^2
-1
-b^2
+a^2 =b
²(a²-1)+(a²-1)=(a²-1)(b²+1)=(a-1)(a+1)(b²+1)
3 votes
Thanks 4
dashutailyashe
Спасибо!
ytekjdbvsq
В первом примере из второй скобки выносим (–2у^2) и тогда во второй скобке будет (х-4)
ytekjdbvsq
В первом примере у Вас разные скобки, поэтому (х+4) не является общим множителем
MizoriesKun
спасибо
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Answers & Comments
Verified answer
2x^3-2xy^2-8x^2+8y^2 =2x²(х-4)-2у²(х-4) =(х-4)(2х²-2у²)=2(х-4)(х²-у²)==2(х-4)*х-у)*(х+у)
5a^2-5b^2-15a^3b+15ab^3=5(a²-b²)-15ab(a²-b²)=(a²-b²)(5-15ab)=
=5(a-b)(a+b)(1-3ab)
a^2b^2-1-b^2+a^2 =b²(a²-1)+(a²-1)=(a²-1)(b²+1)=(a-1)(a+1)(b²+1)