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YUMMU
@YUMMU
April 2022
2
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Представьте в виде произведения многочлен:
1) B^2-4
2) X^2+8-4
3) y^3+27
4) z^3-1
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Exometr
1)в^2-4=(в-2)(в+2)
4)z^3-1=(z-1)(z^2+z+1)
1 votes
Thanks 1
krugly1981
1) b² - 4 = b² - 2² = ( b - 2)(b + 2)
2) x² + 8 - 4 = (x² - 4) + 8 = ( x - 2)(x + 2) + 8
3) y³ + 27 = y³ + 3³ = ( y + 3)(y² - 3y + 9)
4) z³ - 1 = z³ - 1³ = ( z - 1)(z² + z + 1)
2 votes
Thanks 1
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Answers & Comments
4)z^3-1=(z-1)(z^2+z+1)
2) x² + 8 - 4 = (x² - 4) + 8 = ( x - 2)(x + 2) + 8
3) y³ + 27 = y³ + 3³ = ( y + 3)(y² - 3y + 9)
4) z³ - 1 = z³ - 1³ = ( z - 1)(z² + z + 1)