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18Сашуля
@18Сашуля
July 2022
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Представьте в виде произведения многочлен b°2-x°2+2xy-y°2
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sedinalana
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B²-x²+2xy-y²=b²-(x²-2xy+y²)=b²-(x-y)²=(b-x+y)(b+x-y)
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Verified answer
B²-x²+2xy-y²=b²-(x²-2xy+y²)=b²-(x-y)²=(b-x+y)(b+x-y)