1)b^(-6+4)=b^-2
2)b^(2-(-7))=b^9
3)b^((-5*(-2))-8)=b^2
1) = b^(-6+4) = b^-2 = 1/b^2
2) = b^(2-(-7)) = b^9
3) = b^(-5*(-2) + (-8)) = b^(10-8) = b^2
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Verified answer
1)b^(-6+4)=b^-2
2)b^(2-(-7))=b^9
3)b^((-5*(-2))-8)=b^2
Verified answer
1) = b^(-6+4) = b^-2 = 1/b^2
2) = b^(2-(-7)) = b^9
3) = b^(-5*(-2) + (-8)) = b^(10-8) = b^2