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PruFFI
@PruFFI
July 2022
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Преобразовать произведение в сумму
sin(60°+a)sin(60°-a)
a- альфа
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Answers & Comments
nKrynka
Sin(60°+a)sin(60°-a) = (1/2)*[cos(60° + α - 60° + α
) -
- cos(
60° + α + 60° - α)] = (1/2)*[cos2α - cos(120°)] =
= (1/2)*[cos2α + cos(60°)] = (1/2)*[cos2α + 1/2)] = (1/2)*cos2α + 1/4
6 votes
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Answers & Comments
- cos(60° + α + 60° - α)] = (1/2)*[cos2α - cos(120°)] =
= (1/2)*[cos2α + cos(60°)] = (1/2)*[cos2α + 1/2)] = (1/2)*cos2α + 1/4