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neketkrut123
@neketkrut123
July 2022
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Преобразуйте алгебраическое выражение в многочлен стандартного вида: 3*(2-x)^2-(2x^2+x-5)*(x^2-2)+(x^2+4)*(4-x^2)
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Шипасый
3*(2-x)^2-(2x^2+x-5)*(x^2-2)+(x^2+4)*(4-x^2) =
= 6^2 - 3х^2 - 2х^4 + 4х^2 - х^3 + 2х - 5х^2 + 10 + 4х^2 - х^4 + 16 - 4х^2 =
= 10^2 - 8х^2 - 3^4 - х^3 + 2х + 10
0 votes
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tamarabernukho
3*(2-x)^2-(2x^2+x-5)*(x^2-2)+(x^2+4)*(4-x^2)=
=3(4-4x+x
²)-(2x^4+x³-5x²-4x²-2x+10)+4x²+16-x^4-4x²=
=12-12x+3x²-2x^4-x³+9x²+2x-10+16-x^4=
=-3x^4-x³+12x²-10x+18
0 votes
Thanks 0
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Answers & Comments
= 6^2 - 3х^2 - 2х^4 + 4х^2 - х^3 + 2х - 5х^2 + 10 + 4х^2 - х^4 + 16 - 4х^2 =
= 10^2 - 8х^2 - 3^4 - х^3 + 2х + 10
=3(4-4x+x²)-(2x^4+x³-5x²-4x²-2x+10)+4x²+16-x^4-4x²=
=12-12x+3x²-2x^4-x³+9x²+2x-10+16-x^4=
=-3x^4-x³+12x²-10x+18