Преобразуйте в многочлен
(1-2d)^3
(5-3y)^2
(8+5y)^2
(4-7n)^3
(2+8c)^3
Упростите выражение
(2-m)^3+4m
(p+8)^3-16p
(10+a)^2-100
(5-y)^3-y^2
(6+n)^2-n2
(7-j)^2-4
(11+k)^3-22k
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4-(2+5k)^4
(6c-5)^2+60c
48y+(3y-0)^3
144q^3 -(3-11q)^3
122p+(8p-7)^3
(9d+1)^2 -18d
Помогите пожалуйста:(
(1-2d)^3
(5-3y)^2
(8+5y)^2
(4-7n)^3
(2+8c)^3
Упростите выражение
(2-m)^3+4m
(p+8)^3-16p
(10+a)^2-100
(5-y)^3-y^2
(6+n)^2-n2
(7-j)^2-4
(11+k)^3-22k
------------
4-(2+5k)^4
(6c-5)^2+60c
48y+(3y-0)^3
144q^3 -(3-11q)^3
122p+(8p-7)^3
(9d+1)^2 -18d
Помогите пожалуйста:(
Answers & Comments
(5-3y)^2=25-15y+9y2
(8+5y)^2=64+40y+25y2
(4-7n)^3=(4-7n)(16+28n+49n2)=64+112n+196n2-112n-196n2-343n3=64-343n3
(2+8c)^3=(2+8c)(4-16c+64c2)=8-32c+128c2+32c-128c2+512c3=8+512c3
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(2-m)^3+4m=(2-m)(4+2m+m2)+4m=8+4m+2m2-4m-2m2-m3+4m=8-m3+4m
(p+8)^3-16p=p3+512-16p
(10+a)^2-100=100+10a+a2-100=10a-a2=a(10-a)
(5-y)^3-y^2=125-y3-y2
(6+n)^2-n2=36+6n+n2-n2=36+6n=6(6+n)
(7-j)^2-4=49-7j+j2-4=48-7j+j2
(11+k)^3-22k=1331+k3-22k
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