Преобразуйте в многочлен:
1) (x-4)^2
2) (3x-5)^2
3) (2a-3) (2a+3)
4) (y^2-2) (y^2+2)
1) (x-4)^2
2) (3x-5)^2
3) (2a-3) (2a+3)
4) (y^2-2) (y^2+2)
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Answers & Comments
Verified answer
1) (x-4)^2=x^2-8x+162) (3x-5)^2=9x^2-30x+25
3) (2a-3) (2a+3)=4a^2-9
4) (y^2-2) (y^2+2)=y^4-4
2)9*(x^2)-2*3*x*5+25
3)(2a^2)-9
4)(y^4)-2^2
Скорее всего так )