Преобразуйте в многочлен: (a-8)(a+8)-5a(6-a)=
(a-3)(a-2)-(a-4)²=
(b+2)(b-2)+(5b+4)²=
5(a+2)²-(5a²+29a)=
(5x-4)²-3x(5-x)=
(p+8)(p-3)+(p+7)²=
(a-x)²+(a+x)²=
(2ab-b²)+2(a-b)²=
(a-3)(a-2)-(a-4)²=
(b+2)(b-2)+(5b+4)²=
5(a+2)²-(5a²+29a)=
(5x-4)²-3x(5-x)=
(p+8)(p-3)+(p+7)²=
(a-x)²+(a+x)²=
(2ab-b²)+2(a-b)²=
More Questions From This User See All