4*(3/4-(1/4)*cos²α)=4*((√3/2)*0.5-0.5cosα)
3-4cos²α=3-4(1-sin²α)=3-4+4sin²α=(2sinα-1)(2sinα+1)=
(1/4)*(sinα-1/2)(sinα+1/2)=(1/4)*(sinα-sin30°)(sinα+sin30°)=
(1/4)*((2*(sin(α-30°)/2)(cos(α+30°)/2))*2*(sin(α+30°)/2)(cos(α-30°)/2))=
(1/4)*((sin(α-30°))(sin(α+30°))
Bоспользовались заменой 1/2- это sin30°; и формулами
sinα-sinβ=2sin((α-β°)/2)(cos(α+β)/2)
и sinα+sinβ=2sin((α+β°)/2)(cos(α-β)/2)
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Answers & Comments
4*(3/4-(1/4)*cos²α)=4*((√3/2)*0.5-0.5cosα)
3-4cos²α=3-4(1-sin²α)=3-4+4sin²α=(2sinα-1)(2sinα+1)=
(1/4)*(sinα-1/2)(sinα+1/2)=(1/4)*(sinα-sin30°)(sinα+sin30°)=
(1/4)*((2*(sin(α-30°)/2)(cos(α+30°)/2))*2*(sin(α+30°)/2)(cos(α-30°)/2))=
(1/4)*((sin(α-30°))(sin(α+30°))
Bоспользовались заменой 1/2- это sin30°; и формулами
sinα-sinβ=2sin((α-β°)/2)(cos(α+β)/2)
и sinα+sinβ=2sin((α+β°)/2)(cos(α-β)/2)