преобразуйте выражение в многочлен стандартного вида: 2(m+1)^2+3(m+2)^2
2(m+1)²+3(m+2)²=2(m²+2m+1)+3(m²+4m+4)=2m²+4m+2+3m²+12m+12=5m²+16m+14
2(m+1)^2+3(m+2)^2=2(m^2+2m+1)+3(m^2+4m+4)=2m^2+4m+2+3m^2+12m+12=5m^2+16m+14
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2(m+1)²+3(m+2)²=2(m²+2m+1)+3(m²+4m+4)=2m²+4m+2+3m²+12m+12=5m²+16m+14
2(m+1)^2+3(m+2)^2=2(m^2+2m+1)+3(m^2+4m+4)=2m^2+4m+2+3m^2+12m+12=5m^2+16m+14