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nastyasohina
@nastyasohina
June 2022
2
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При диссоциации хлорида калия в растворе присутствуют частицы
а) K+ б)cl+ в)k- г)cl-
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informatikschop22sei
Verified answer
KCl=K⁺+Cl⁻
a), г)
.........................................
2 votes
Thanks 3
суперкoт1
KCI=K+CI
Варианты А и Г
1 votes
Thanks 3
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Verified answer
KCl=K⁺+Cl⁻a), г)
.........................................
Варианты А и Г