AgNO3+NaCl=AgCl+NaNO3
v(AgCl)=0.01мль
v(AgNO3)=v(AgCl)
m(AgNO3)=0.01моль*170г/моль=17г
m(AgCl)=1,44г
M(AgNO3)=170г
M(AgCl)=143,5г
m(AgNO3)=170*1,44/144=1,7гр
Ответ:1,7 гр
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AgNO3+NaCl=AgCl+NaNO3
v(AgCl)=0.01мль
v(AgNO3)=v(AgCl)
m(AgNO3)=0.01моль*170г/моль=17г
AgNO3+NaCl=AgCl+NaNO3
m(AgCl)=1,44г
M(AgNO3)=170г
M(AgCl)=143,5г
m(AgNO3)=170*1,44/144=1,7гр
Ответ:1,7 гр