При горении водорода в кислороде образовалась вода массой 14,4 г. Вычислить масс...

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При горении водорода в кислороде образовалась вода массой 14,4 г. Вычислить массу вступившего водорода.

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anassstass M (H2O) = 14,4 г
2H2 + O2 — 2H2O
m (H2) - ?

M (H2O) = 18 г/моль
M (H2) = 2 г/моль
n (H2O) = m/M = 0,8 моль
2H2 + O2 — 2H2O
n (H2) = 0,8 • 2 / 2 = 0,8 моль
m (H2) = nM = 0,8 • 2 = 1,6 г
Ответ: 1,6 г

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