Q=500 Дж i=3 v=2 моль ΔU=?
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p=const
Q=ΔU+A
Q=(i+2)*v*R*ΔT/2
A=v*R*ΔT=2*Q/(i+2)
ΔU=Q-A=Q - 2*Q/(i+2)=500 - 2*500/(3+2)=300 Дж
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Q=500 Дж i=3 v=2 моль ΔU=?
===
p=const
Q=ΔU+A
Q=(i+2)*v*R*ΔT/2
A=v*R*ΔT=2*Q/(i+2)
ΔU=Q-A=Q - 2*Q/(i+2)=500 - 2*500/(3+2)=300 Дж
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