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Aqry
@Aqry
August 2022
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При каких значениях b нет корней
x²+bx+16=0
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sedinalana
Нет корней,если дискриминант меньше 0
x²+bx+16=0
D=b²-4*1*16=b²-64=(b-8)(b+8)<0
b=8 b=-8
+ _ +
--------------(-8)--------------(8)---------------
b∈(-8;8)
2 votes
Thanks 1
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Answers & Comments
x²+bx+16=0
D=b²-4*1*16=b²-64=(b-8)(b+8)<0
b=8 b=-8
+ _ +
--------------(-8)--------------(8)---------------
b∈(-8;8)