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@2шка
June 2022
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при каких значениях х верно равенство. (х+2)*4=2*4+2*4. (5-3)х=5х-3х. (5-3)х=5х-3*2
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Krsavec
1)(х+2)*4=2*4+2*4
4х+8=8+8
4х=8
х=8:4
х=2
2)(5-3)х=5х-3х
5х-3х-5х+3х=0
0=0
3)(5-3)х=5х-3*2
5х-3х=5х-6
5х-3х-5х=-6
-3х=-6
х=-6:(-3)
х=2
1 votes
Thanks 2
Anuta11111
1) (x+2)×4=2×4+2×4
(x+2)×4=16
x+2=16:4
x+2=4
x=4-2
x=2
(2+2)×4=2×4+2×4
16=16
2) (5-3)×x=5x-3x
2x=2x
3)(5-3)×x=5x-3×2
2x=5x-6
1 votes
Thanks 2
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Answers & Comments
4х+8=8+8
4х=8
х=8:4
х=2
2)(5-3)х=5х-3х
5х-3х-5х+3х=0
0=0
3)(5-3)х=5х-3*2
5х-3х=5х-6
5х-3х-5х=-6
-3х=-6
х=-6:(-3)
х=2
(x+2)×4=16
x+2=16:4
x+2=4
x=4-2
x=2
(2+2)×4=2×4+2×4
16=16
2) (5-3)×x=5x-3x
2x=2x
3)(5-3)×x=5x-3×2
2x=5x-6