при x³-16x≥0
x(x²-16)≥0
x(x-4)(x+4)≥0
x∈[-4;0]∪[4;+∞)
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при x³-16x≥0
x(x²-16)≥0
x(x-4)(x+4)≥0
x∈[-4;0]∪[4;+∞)