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@linaaaaaaaaaa
July 2022
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при каких значениях параметра m уравнение х²+4х+m-3=0 имеет ровно один корень? УМОЛЯЮ ПОМОГИТЕ♥♥♥
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mukus13
Verified answer
X²+4x+(m-3)=0
D=16-4(m-3)=16-4m+12=28-4m=0
4m=28
m=7
---------------------
x²+4x+4=(x+2)²=0
x=-2
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Answers & Comments
Verified answer
X²+4x+(m-3)=0D=16-4(m-3)=16-4m+12=28-4m=0
4m=28
m=7
---------------------
x²+4x+4=(x+2)²=0
x=-2