При каких значениях параметра p точка пересечения прямых px+3y=-p и 3x+py=8 лежит либо в первой четверти координатной плоскости либо на одной из осей координат? (-3;0]
Answers & Comments
ортртгн
Simplifying3x + -1py + -3y + px = 0Reorder the terms:px + -1py + 3x + -3y = 0Solvingpx + -1py + 3x + -3y = 0Solving for variable 'p'.Move all terms containing p to the left, all other terms to the right.Add '-3x' to each side of the equation.px + -1py + 3x + -3x + -3y = 0 + -3xCombine like terms: 3x + -3x = 0px + -1py + 0 + -3y = 0 + -3xpx + -1py + -3y = 0 + -3xRemove the zero:px + -1py + -3y = -3xAdd '3y' to each side of the equation.px + -1py + -3y + 3y = -3x + 3yCombine like terms: -3y + 3y = 0px + -1py + 0 = -3x + 3ypx + -1py = -3x + 3yReorder the terms:px + -1py + 3x + -3y = -3x + 3x + 3y + -3yCombine like terms: -3x + 3x = 0px + -1py + 3x + -3y = 0 + 3y + -3ypx + -1py + 3x + -3y = 3y + -3yCombine like terms: 3y + -3y = 0px + -1py + 3x + -3y = 0The solution to this equation could not be determined.
Answers & Comments