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Koetane
@Koetane
July 2022
2
8
Report
При каких значениях параметра
p
уравнение
x
2
+px+24=0
имеет корень, равный 8.
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Answers & Comments
spikey
X^2+px+24=0
64+8p+24=0
8p=-88
p=-11
3 votes
Thanks 2
Koetane
x^2
HIPM
Wrong answer!
spikey
не увидел квадрат
HIPM
По теореме Виета x1 + x2 = -b, x1 × x2 = c
8 × x2 = 24
x2 = 3
x1 + x2 = -b
3 + 8 = 11 => p = -11 (-b = p)
Ответ: при p = -11
2 votes
Thanks 2
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Answers & Comments
64+8p+24=0
8p=-88
p=-11
8 × x2 = 24
x2 = 3
x1 + x2 = -b
3 + 8 = 11 => p = -11 (-b = p)
Ответ: при p = -11