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Liza14062002
@Liza14062002
July 2022
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при каких значениях параметра t имеет единственный корень уравнение
x^2-(2t-1)x+t^2+t-2=0
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mikael2
Verified answer
X²-(2t-1)x +t²+t-2=0 условие единственности корня D=0
D=(2t-1)²-4*1*(t²+t-2)=4t²-4t+1-4t²-4t+8=-8t+9=0 8t=9 t=9/8
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Answers & Comments
Verified answer
X²-(2t-1)x +t²+t-2=0 условие единственности корня D=0D=(2t-1)²-4*1*(t²+t-2)=4t²-4t+1-4t²-4t+8=-8t+9=0 8t=9 t=9/8