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krevetka32
@krevetka32
August 2022
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При каких значениях x функция y=2x²-11x+5 принимает значение, равное -7?
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olga715
При х= 4
y=2*16-11*4+5= 36-44+5=-7
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Lesben
Y=2x²-11x+5 , y=-7
2x²-11x+5=-7
2x²-11x+12=0, D=121-96=25,√D=√25=5
x1=(11+5)/4=16/4=4
x2=(11-5)/4=6/4=3/2=1,5
Otvet: x=4 i x=1,5
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Answers & Comments
y=2*16-11*4+5= 36-44+5=-7
2x²-11x+5=-7
2x²-11x+12=0, D=121-96=25,√D=√25=5
x1=(11+5)/4=16/4=4
x2=(11-5)/4=6/4=3/2=1,5
Otvet: x=4 i x=1,5