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artem372002
@artem372002
June 2022
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При каких значениях x трёхчлен x^2+12x−24 принимает значение, равное 2?
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wejde
Verified answer
X²+12x-24=2
x²+12x-26=0
D=12²+4*26=144+104=248
√D=√248=√2*2*2*31=2√62
x=(-12+2√62)/2=√62-6
x=(-12-2√62)/2=-6-√62
Ответ: x=-6+√62; x=-6-√62
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Answers & Comments
Verified answer
X²+12x-24=2x²+12x-26=0
D=12²+4*26=144+104=248
√D=√248=√2*2*2*31=2√62
x=(-12+2√62)/2=√62-6
x=(-12-2√62)/2=-6-√62
Ответ: x=-6+√62; x=-6-√62