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annkordonak
@annkordonak
July 2022
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При каком значении b график функции y=x^2+bx-2 проходит через точку А(-3;-5).
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Regent1828
Verified answer
-5 = (-3)² - 3b - 2
3b = 9 + 5 - 2
3b = 12
b = 12 : 3
b = 4
Ответ: {4}
1 votes
Thanks 1
ангел552
-5=(-3)^2-3b-2
-5=9-3b -2
3b=9-2+5
3b=12
b=4
1 votes
Thanks 1
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Answers & Comments
Verified answer
-5 = (-3)² - 3b - 23b = 9 + 5 - 2
3b = 12
b = 12 : 3
b = 4
Ответ: {4}
-5=9-3b -2
3b=9-2+5
3b=12
b=4