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korbeya
@korbeya
July 2022
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при каком значении параметра m уравнение (m-2)х^2-(3m-6)х+12=0 имеет только один корень?
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2407Alexa
Когда D=0
D=(3m-6)^2-4*(m-2)*12=0
9m^2-36m+36-48m+96=0
9m^2-84m+132=0
D=(-84)^2-4*9*132=7056-4752=2304=
=48^2
m1=(-(-84)+48)/2*9=132/18=22/3
m2=(-(-84)-48)/18=36/18=2
2 votes
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Answers & Comments
D=(3m-6)^2-4*(m-2)*12=0
9m^2-36m+36-48m+96=0
9m^2-84m+132=0
D=(-84)^2-4*9*132=7056-4752=2304=
=48^2
m1=(-(-84)+48)/2*9=132/18=22/3
m2=(-(-84)-48)/18=36/18=2