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oska02
@oska02
November 2021
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При нагревании 0,5 моль H2SiO3 на сколько грамм уменьшится его масса?
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likamagomedova03
M (H2SiO3) = 78 г/моль
n (O) = 3*n (H2SiO3)
n (H2SiO3) = n (O) / 3=0,5/3=0.167 моль
m (H2SiO3) = M (H2SiO3) * n (H2SiO3) =
=78*0,167=13.026 г
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Answers & Comments
M (H2SiO3) = 78 г/моль
n (O) = 3*n (H2SiO3)
n (H2SiO3) = n (O) / 3=0,5/3=0.167 моль
m (H2SiO3) = M (H2SiO3) * n (H2SiO3) =
=78*0,167=13.026 г