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дано

m(спирта) = 3 g

V(CO2) = 3.36 L

m(H2O) = 3.6 g

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M(CnH2nOH)-?

n(C) = n(CO2) = V(CO2) / Vm = 3.36 / 22.4 = 0.15 mol

M(C) = 12 g/mol

m(C) = n*M = 0.15 * 12 = 1.8 g

n(H) = 2n(H2O) = 2* (3.6 / 18) = 0.4 mol

M(H) = 1 g/mol

m(H) = n*M = 0.4 * 1  = 0.4 g

m(O) = m(CnH2nOH)  - ( m(C)+m(H)) = 3 - ( 1.8 + 0.4) = 0.8 g

M(O) = 16 g/mol

n(O) = m/M = 0.8 / 16 = 0.05 mol

n(C) : n(H) : n(O) = 0.15 :0.4 : 0.05 = 3 : 8 :1

C3H7OH

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