дано
V(CO2) = 16.8 дм3
m(H2O) = 16.2 g
D(Ar) = 1.8
------------------
CxHy-?
M(CxHy) = D(Ar) *1.8 = 40 * 1.8= 72 g/mol
n(C) = n(CO2) = 16.8 / 22.4 = 0.75 mol
n(H2O) = 16.2 / 18 = 0.9 mol
n(H) = 0.9 * 2 = 1.8 mol
n(C) : n(H) = 0.75 : 1.8 = 5:12
C5H12
M(C5H12) = 72 g/mol
ответ C5H12
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Answers & Comments
дано
V(CO2) = 16.8 дм3
m(H2O) = 16.2 g
D(Ar) = 1.8
------------------
CxHy-?
M(CxHy) = D(Ar) *1.8 = 40 * 1.8= 72 g/mol
n(C) = n(CO2) = 16.8 / 22.4 = 0.75 mol
n(H2O) = 16.2 / 18 = 0.9 mol
n(H) = 0.9 * 2 = 1.8 mol
n(C) : n(H) = 0.75 : 1.8 = 5:12
C5H12
M(C5H12) = 72 g/mol
ответ C5H12