T1=273+27=300 K T2=273+52=325 K ΔV=2*10^-3 м3 V1=?
V1/T1=V2/T2 V2=V1+ΔV
V1=ΔV/(t2/T1-1)=2*10^-3/(325/300-1)=24.1*10^-3 м3 (24,1 л)
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T1=273+27=300 K T2=273+52=325 K ΔV=2*10^-3 м3 V1=?
V1/T1=V2/T2 V2=V1+ΔV
V1=ΔV/(t2/T1-1)=2*10^-3/(325/300-1)=24.1*10^-3 м3 (24,1 л)
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