July 2022 1 5 Report
при сгорание некоторого углеводорода образовалось 6,72 литра углекислого газа и 5,4 г воды определите молекулярную формулу углеводорода если плотность его паров по водорожу равна 21
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments

More Questions From This User See All
reshenie cepochki i ovr srochno
Answer
dopishite uravneniya reakcij 1 ch3 ch2 co ch3hoh o 2 ch3 coho ch2 ch3
Answer
sostavte plan teksta0b1db5b19d0078144a83c126836e06b9 7775
Answer
yunye biologi reshite 2 zadachu pozhalujsta
Answer
reshite cepochku feoh3 fe2o3 fe2so43
Answer
Cu-CuO-CuCl2-Cu(OH)2-CuCl2...
Answer
kak iz pboh2 sdelat pbcl2
Answer
osushestvite prevrashenie oksid cinka cink vodorod hlorovodorod dlya vtor
Answer
dany veshestva oksid sery4 gidroksid natriya solyanaya kislota oksid kalciya i
Answer
sostavte plan teksta po ekonomike
Answer

рекомендуемые вопросы

o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.