September 2021 1 4 Report
При спалюванні 28л вуглеводню утворилось 112л вуглекислого газу(н.у.) і 67,2г води. Густина за воднем 27. Визначити молекулюрну формулу речовини.
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vnaslidok spalennya 23g rechovini utvorilosya 44g oksidu karbonu iv i 27g vodi
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