Ответ:

дано

m(CH3COOH) = 64 g

m(C2H5OH) = 10 g

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m(CH3COOC2H5)-?

M(CH3COOH) = 60 g/mol

n(CH3COOH) = m(CH3COOH) / M(CH3COOH) = 64 / 60 = 1.07 mol

M(C2H5OH) = 46 g/mol

n(C2H5OH) = m(C2H5OH) / M(C2H5OH) = 10 / 46 = 0.22 mol

n(CH3COOH) > n(C2H5OH)

M(CH3COOC2H5) = 88 g/mol

CH3COOH+C2H5OH-->CH3COOC2H5+H2O

n(C2H5OH) = n(CH3COOC2H5) = 0.22 mol

m(CH3COOC2H5) = n(CH3COOC2H5) * M(CH3COOC2H5)

m(CH3COOC2H5) = 0.22 * 88 = 19.36 g

ответ 19.36 г

Объяснение: