mgco3+hbr=co2+h2o+mgbr2
М(hbr)=81 г/моль
n(hbr)=146/81=1.8 моль
M(mgco3)=12+48+24=84 г/моль
n(mgco3)=n(hbr)
1.8=X/84
X=1.8*84=151.2 г
151.2+146=297.5 г
U(омега)=(146/297,2)*100%=49.1%
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mgco3+hbr=co2+h2o+mgbr2
М(hbr)=81 г/моль
n(hbr)=146/81=1.8 моль
M(mgco3)=12+48+24=84 г/моль
n(mgco3)=n(hbr)
1.8=X/84
X=1.8*84=151.2 г
151.2+146=297.5 г
U(омега)=(146/297,2)*100%=49.1%