Ca+2HCl= CaCl2 +H2
12гр × 22.4 л / 40 гр (Са) = 6.72л (Н2)
Ответ : Н2 - 6.72л
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Ca+2HCl= CaCl2 +H2
12гр × 22.4 л / 40 гр (Са) = 6.72л (Н2)
Ответ : Н2 - 6.72л