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aisaulelove
@aisaulelove
July 2022
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Приведите к тригонометрической функции угла от (0°;90°):
а) tg 137°; б) sin ( — 178°); в) sin 680°; г) cos ( —1000°).
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DumagedDon
Verified answer
A) tg137 = tg(90 +47) = -ctg47
b) sin(-178) = -sin(90 + 88) = - cos88
v) sin680 = sin(720 - 40) = sin(-40) = -sin40
g) cos(-1000) = cos1000 = cos(3*360 - 80) = cos(-80) = cos80
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Answers & Comments
Verified answer
A) tg137 = tg(90 +47) = -ctg47b) sin(-178) = -sin(90 + 88) = - cos88
v) sin680 = sin(720 - 40) = sin(-40) = -sin40
g) cos(-1000) = cos1000 = cos(3*360 - 80) = cos(-80) = cos80