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mihalkovadasha
@mihalkovadasha
July 2022
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приведите механизм реакции хлорирования бутана.
CH3-CH2-CH2-CH3+Сl2--->{hv}
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xАнонимx
Зарождение цепи: Cl2 --(hv)--> 2Cl•
Рост цепи: CH3-CH2-CH2-CH3 + Cl• --> CH3-C•H-CH2-CH3 + HCl
CH3-C•H-CH2-CH3 + Cl2 --> CH3-CHCl-CH2-CH3 + Cl•
...
Обрыв цепи: 2Cl• --> Cl2
CH3-C•H-CH2-CH3 + Cl• --> CH3-CHCl-CH2-CH3
2CH3-C•H-CH2-CH3 --> CH3-CH2-CH(-CH3)-CH(-CH3)-CH2-CH3
3 votes
Thanks 6
mihalkovadasha
спасибо большое))
xАнонимx
Угу)Нез
HUH39I
Verified answer
CH3-CH2-CH2-CH3 + Cl2 --hv-->CH3-CHCl-CH2-CH3+ HCl 2CH3-CHCl-CH2-CH3+ 2Na ----> CH3-CH2-CH(CH3)-CH(CH3)-CH2-CH3 + 2NaCl CH3-CHBr-CH(CH3)2 + KOH --C2H5OH--> (CH3)2C=CH-CH3 + KBr + H2O n(CH3)2C=CH-CH3 --Kat--> [-C(CH3)2-CH(CH3)-]n
Вот держи)Надеюсь поможет :)
3 votes
Thanks 8
mihalkovadasha
спасибо)))
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Answers & Comments
Рост цепи: CH3-CH2-CH2-CH3 + Cl• --> CH3-C•H-CH2-CH3 + HCl
CH3-C•H-CH2-CH3 + Cl2 --> CH3-CHCl-CH2-CH3 + Cl•
...
Обрыв цепи: 2Cl• --> Cl2
CH3-C•H-CH2-CH3 + Cl• --> CH3-CHCl-CH2-CH3
2CH3-C•H-CH2-CH3 --> CH3-CH2-CH(-CH3)-CH(-CH3)-CH2-CH3
Verified answer
CH3-CH2-CH2-CH3 + Cl2 --hv-->CH3-CHCl-CH2-CH3+ HCl 2CH3-CHCl-CH2-CH3+ 2Na ----> CH3-CH2-CH(CH3)-CH(CH3)-CH2-CH3 + 2NaCl CH3-CHBr-CH(CH3)2 + KOH --C2H5OH--> (CH3)2C=CH-CH3 + KBr + H2O n(CH3)2C=CH-CH3 --Kat--> [-C(CH3)2-CH(CH3)-]nВот держи)Надеюсь поможет :)