Приведите уравнение к виду ах(в квадрате)+bx+c=0  1: (х+3)(3х-2)=(4х+5)(2х-3) 2: 4х(в квадрате)-2х(3х+1)=5  3: х(в квадрате)+(1-х)(1-3х)=х  4:   (3х+2)(в квадрате)=(х+2)(х-3)
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