March 2021 0 3 Report
Привести уравнение кривой второго порядка f(х;у)=0 к каноническому виду и найти точки пересечения ее с прямой Ах+Ву+С=0.Выполните графическую иллюстрацию полученного решения. х - 2у(в квадрате) + 4у - 3=0 ; x - 2у + 1=0

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