2^7х-8=8^2
2^7х-8=2^6
7х-8=6
х=2
5*0,25=1,25
1) (7x-8)*log (2) = 2
(7x-8)*(1/3) =2
7x - 8 = 6
7x= 14
x = 2
2) cos 2a = cos^2 (a) - sin^2(a)
sin(a) = корень квадр.(1-cos^2(a)) = корень квадр.(1-1/4) = корень квадр.(3) / 2
5*cos 2a = 5*(1/4-3/4) = 5*(-2/4) = -5/2 = -2.5
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Answers & Comments
2^7х-8=8^2
2^7х-8=2^6
7х-8=6
х=2
5*0,25=1,25
1) (7x-8)*log (2) = 2
(7x-8)*(1/3) =2
7x - 8 = 6
7x= 14
x = 2
2) cos 2a = cos^2 (a) - sin^2(a)
sin(a) = корень квадр.(1-cos^2(a)) = корень квадр.(1-1/4) = корень квадр.(3) / 2
5*cos 2a = 5*(1/4-3/4) = 5*(-2/4) = -5/2 = -2.5