Ответ:
#include <iostream>
#include <math.h>
using namespace std ;
int main() {
double x, y, z, a, b;
cin >> x >> y>> z ;
a = y + x/(y*y + abs(x*x/(y+x*x*x/3)));
b = (1 + pow(tan(z/2),2));
cout << a << endl <<b ;
return 0 ;
}
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Answers & Comments
Ответ:
#include <iostream>
#include <math.h>
using namespace std ;
int main() {
double x, y, z, a, b;
cin >> x >> y>> z ;
a = y + x/(y*y + abs(x*x/(y+x*x*x/3)));
b = (1 + pow(tan(z/2),2));
cout << a << endl <<b ;
return 0 ;
}